x²-x-2=0x²-x=2原式=(x²-x)²-1+(x²-x+2√3)/√3带入x²-x=2到上式得到：2²-1+(2+2√3)/√3=3+2√3/3+2=5+2√3/3
把前式中x解出，带入二式就好了吧
