解下列方程:(1)x2-4x-45=0;(2)8y2-2=4y(配方法);(3)2(x2-1)=3(x-1);(4)2x2-4x-5=0(公

2025-04-28 19:43:20
推荐回答(1个)
回答1:

(1)(x-9)(x+5)=0,
∴x-9=0或x+5=0,
解得x1=9,x2=-5;

(2)8y2-4y-2=0,
y2-

1
2
y=
1
4

y2-
1
2
y+
1
16
=
5
16

(y?
1
4
)
2
=
5
16

y-
1
4
5
4

y=
1
4
±
5
4

∴y1=
1+
5
4
,y2=
1?
5
4


(3)2(x+1)(x-1)-3(x-1)=0,
(x-1)(2x+2-3)=0,
∴x-1=0或2x-1=0,
解得x1=1,x2=
1
2


(4)2x2-4x-5=0,
a=2,b=-4,c=-5,
△=16+40=56,
x=