先化简,再求值:1-(x-1⼀1-x)^2÷x^2-x+1⼀x^2-2x+1,其中x^2-x+5=0

2024-12-01 03:15:38
推荐回答(1个)
回答1:

1-(x-1/1-x)^2÷x^2-x+1/x^2-2x+1,其中x^2-x+5=0
=1-(x-x²-1)²/(1-x)²÷(x²-x+1)/(x-1)²
=1-(x²-x+1)²/(x²-x+1)
=1-x²+x-1
=-(x²-x)
=-(-5)
=5