这显然是一个26进制数向10进制转化的题目。用pascal吧! fortran处理字符串或者字符性能较弱 !
{$n+e-}
var
s:string;
n:integer;
a:array[0..100] of integer;
i,j:integer;
sum:extended;
begin
s:='zzzzzzzzz';
n:=length(s);
for i:=1 to n do begin
a[i]:=ord(s[i])-ord('a');
end;
sum:=0.0;
for i:=1 to n do begin
sum:=sum*26+a[i];
end;
writeln(sum);
end.