你好！3(m-2)² + 1 = 2m+1 + 23m² - 12m + 12 - 2m - 2 = 03m² - 14m + 10 = 0m = (7±√19)/3
3（m-2）^2+1-(2m+1)=23m^2-12m+12+1-2m-1-2=03m^2-12m+12+1-2m-1-2=03m^2-14m+10=0用求根公式求M
