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13问答网 > 求傅里叶变换 f（t）=sin（πt⼀2）G4（t）

求傅里叶变换 f（t）=sin（πt⼀2）G4（t）

2025-03-15 20:47:59

推荐回答（1个）

回答1：

由三倍角公式：sin3t=3sint-4sin3t,得：sin3t=(3sint-sin3t)/4则sinat的傅里叶变换为jπ[δ(w+a)-δ(w-a)]所以f(t)的傅里叶变换为F(w)=jπ{[3δ(w+1)-3δ(w-1)]-[δ(w+3)-δ(w-3)]}/4

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