因为x^2=(x-1)^2 + 2(x-1) + 1得∫x^2/(x-1)^10=[(x-1)^2 + 2(x-1) + 1]/(x-1)^10 dx=∫[(x-1)^(-8) + 2(x-1)^(-9) + (x-1)^(-10)]dx=-[(x-1)^(-7)/7 + (x-1)^(-8)/4 + (x-1)^(-9)/9]
