4(x-3)的平方-(x+3)的平方=2(x-5)(x-1)
4(X²-6X+9)-(X²+6X+9)=2(X²-X-5X+5)
4X²-24X+36-X²-6X-9=2X²-2X-10X+10
4X²-X²-2X²-24X-6X+2X+10X+36-9-10=0
X²-18X+17=0
(X-1)(X-17)=0
X1=1,X2=17
方法二:4(x-3)的平方-(x+3)的平方=2(x-5)(x-1)
【2(x-3)+(x+3)】【2(x-3)-(x+3)】=2(x-5)(x-1)
(3x-3)(x-9)=2(x-5)(x-1)
3(x-1)(x-9)-2(x-5)(x-1)=0
(x-1)【3(x-9)-2(x-5)】=0
x-1=0,3(x-9)-2(x-5)=0
x1=1,x2=17