e^y=e^x=sin(xy) 则，(e^y)'-(e^x)'=[sin(xy)]' ==> (e^y)*y'-(e^x)*x'=cos(xy)*(xy)' ==> (e^y)*y'-(e^x)=cos(xy)*(x'*y+x*y') ==> (e^y)*y'-(e^x)=cos(xy)*(y+xy') ==> (e^y)*y'-x*cos(xy)*y'=ycos(xy)+e^x ==> y'=[ycos(xy)+e^x]/[e^y-xcos(x...
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