试用简便方法解方程2⼀1[x-2⼀1(x-1)+1]=2尀3(x-1)

谢谢了详细一点^_^最好是带讲解。求原创!QQ2855753243
2024-11-27 20:08:26
推荐回答(2个)
回答1:

1/2(x-1/2(x-1)-1+2)=2/3(x-1) {将“+1”变为“-1+2”}
1/2((x-1)-1/2(x-1)+2)=2/3(x-1) → 1/2(1/2(x-1)+2)=2/3(x-1)
1/4(x-1)+1=2/3(x-1) {去括号}
5/12(x-1)=1 {移项,合并同类项}
x-1=12/5
x=17/5=3.4

回答2:

首先,2/a=2/b,就是a=b,当然a,b不能为0。
所以x-2/(x-1)+1=2/3(x-1)
去分母x(x-1)-2+(x-1)=2/3
x^2-x+x-11/3=0
x^2=11/3
x=正负(根号33)/3