=2sin[（π/6-a）-π/6]=2sin(-a)=-2sina
√3*sin(π/6-α) - cos(π/6-α)
=2 * [ √3/2*sin(π/6-α) - 1/2*cos(π/6-α) ]
=2 * [ sin(π/6-α)*cos(π/6) - sin(π/6)*cos(π/6-α) ]
=2 * [ sin(π/6-α-π/6) ]
=2 * sin(-α)
=-2*sin(α)
√3（sin30cosα-cos30sinα）-（cos30cosα+sin30sinα）=化简=-2sinα
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