13问答网 > 已知f(根号x+1）=x+1,则函数f(x)的解析式为多少？

已知f(根号x+1）=x+1,则函数f(x)的解析式为多少？

2025-03-17 23:30:49
推荐回答（5个）
回答1：

设t=1 √x,x=(t-1)^2
f(t)=(t-1)^2 1
f(t)=t^2-2t 2 (t>=1)
所以f(x)=t^2-2t 2(x>=1)

回答2：

f（x）=x2，令t=根号x+1，则x=t2-1，所以f（t）=t2，即f（x）=x2,。因为函数用什么字母代表都一样

回答3：

f(x)=x, x>=1

回答4：

f（x）=x的二次方－2x

回答5：

a方-2a+2

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