解:设公比为q,则q>0a1,(1/2)a3,2a2成等差,则2(1/2)a3=a1+2a2a3=a1+2a2a1q²=a1+2a1qq²-2q-1=0(q+1)(q-2)=0q=-1(<0,舍去)或q=2(a2013+a2014)/(a2011+a2012)=(a2011×q²+a2012×q²)/(a2011+a2012)=q²(a2011+a2012)/(a2011+a2012)=q²=2²=4