Sin(25π⼀6)+cos(25π⼀3)+tan(-25π⼀4)=?

2025-02-23 19:53:04
推荐回答(2个)
回答1:

Sin(25π/6)+cos(25π/3)+tan(-25π/4)
=Sin(4π+π/6)+cos(8π+π/3)+tan(-6π-π/4)
=Sin(π/6)+cos(π/3)+tan(-π/4)
=1/2+1/2 -1
=0

回答2:

等于0.5+0.5-1等于0