arctanx⼀x^3 dx的不定积分怎么计算的?要过程,谢谢!

2025-03-04 19:44:21
推荐回答(1个)
回答1:

∫arctanx/x�0�6 dx=∫arctanx/(-1/2x�0�5)=-1/2x�0�5*arctanx-∫-1/2x�0�5 d[1/(x�0�5+1)]→分部积分法=-arctanx/2x�0�5+1/2*∫1/x�0�5(x�0�5+1) dx=-arctanx/2x�0�5+1/2*∫[1/x�0�5-1/(x�0�5+1)] dx=-arctanx/2x�0�5+1/2*∫1/x�0�5 dx-1/2*∫1/(x�0�5+1) dx=-arctanx/2x�0�5+1/2*(-1/x)-1/2*arctanx+C=-(1/2x�0�5)arctanx-1/2x-(1/2)arctanx+C