关于必修4三角函数的题,求解?

2025-04-27 06:37:57
推荐回答(1个)
回答1:

∵(sinα)^2+(cosα)^2=1
(sinα)^2-2sinαcosα+(cosα)^2=1-2sinαcosα
(sinα-cosα)^2=1-2×(1/2)
(sinα-cosα)^2=0
sinα-cosα=0
则sinα-cosα+sinαcosα=1/2