2x²—4x/3—2=02(x²-2x/3+1/9)-2/9-2=02(x-1/3)²=2/9+2(x-1/3)²=10/9 （后面是9分之10）选C
2x^2-(4/3)x-2=0===> x^2-(2/3)x-1=0===> [x^2-(2/3)x+(1/9)]-(1/9)-1=0===> [x^2-(2/3)x+(1/9)]-(10/9)=0===> [x-(1/3)]^2=10/9——答案：C
