求y=aratan(x+1)⼀(x-1)的导数

2025-02-24 14:08:45
推荐回答(1个)
回答1:

y = arctan[(x+1)/(x-1)]
y' = 1 / {1+[(x+1)/(x-1)]²} * [(x+1)' (x-1) - (x+1) (x-1)'] / (x-1)²
= (x-1)² / [(x-1)²+(x+1)²] * (-2)/(x-1)²
= -1/(x²+1)