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13问答网 > 分别写出以石墨,铁棒为电极电解CuSO4 溶液的电极反应和电解池总反应式

分别写出以石墨,铁棒为电极电解CuSO4 溶液的电极反应和电解池总反应式

2025-03-16 03:18:56

推荐回答（3个）

回答1：

解析：一定不一样.
因为Fe做阴极时：阴极： 2Cu2+ + 4e-=2Cu
阳极：4OH- - 4e-=2H2O+O2(^)
总反应式： 2CuSO4 + 2H2O =电解= 2Cu + O2(^)+2H2SO4
若Fe做阳极时：阳极：Fe2- -2e-=Fe
阴极：Cu2+ + 2e-=Cu
总反应式： Fe+CuSO4=Cu+FeSO4
祝学习进步！！！

回答2：

篮球+排球+足球=86，排球+足球=54
所以篮球=86-54=32
篮球+足球=40
所以足球=40-32=8
排球+足球=54
所以排球=54-8=46
如果满意，请点击右下角的【采纳答案】。谢谢

回答3：

不一样的，具体发图给你

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