3^(2m-4n+1)
=3^(2m)/3^(4n)*3
=(3^m)^2/(3^4)^n*3
=6^2/[(3^2)^2]^n*3
=36/(9^2)^n*3
=36/(9^n)^2*3
=36/2^2*3
=27.
3^(2m-4n+1)=3^2m*3/3^4n=3*(3^m)^2/(3^2)^2n=3*6^2/9^2n=108/(9^n)^2=108/2^2=27
3^(2m-4n+1)=3^2m*3^4n*3=6^2/9^2n*3=36/4*3=27
3^(2m-4n+1)={[3^(2m)]/[3^(4n)]}*3
=3*[(3^m)^2]/[(9^n)^2]
=3*(6^2)/(2^2)
=3*36/4
=27
27
内容全部来源于网络收集，如有侵权，请联系网站删除：QQ：24596024