高数问题 ∫x⼀(1-x)dx的不定积分

2025-05-02 08:44:15
推荐回答(1个)
回答1:

答:
∫ [x/(1-x)] dx
=∫ [(x-1+1)/(1-x)] dx
=∫ [-1+1/(1-x)] dx
=-∫ dx-∫ [1/(x-1)] d(x-1)
=-x-ln |x-1| +C