计算曲线积分∫(x+y)dx+(y-x)dy,其中L是O(1,1)点经过A(2,1).再到H(2,

2025-03-04 07:17:35
推荐回答(1个)
回答1:

应该是L=OA+AH,直接计算:
∫(x+y)dx-(x-y)dy
=∫OA(x+y)dx-(x-y)dy+∫AH(x+y)dx-(x-y)dy
=∫(0,1)(x)dx+∫(0,1)(-1+y)dy
=1/2-1+1/2=0