如果等差数列{an}的前4项的和是2,前9项的和是-6,求其前n项和的公式

2025-02-28 03:03:45
推荐回答(1个)
回答1:

设公差为d
S4=4a1+6d=2
a1+(3/2)d=1/2 (1)
S9=9a1+36d=-6
a1+4d=-2/3 (2)
(2)-(1)
(5/2)d=-7/6
d=-7/15,代入(2)
a1=-2/3 -4d=-2/3-(-7/15)×4=18/15
Sn=na1+n(n-1)d
=(18/15)n+(-7/15)[n(n-1)]
=n(25-7n)/15