求函数的近似值:arctan1.02

2025-03-09 20:17:41
推荐回答(1个)
回答1:

1)y=e^x
dy=e^xdx
x=1,dx=0.01,dy=e^1 dx=0.01e
所以e^1.01=e+0.01e=1.01e

2)y=arctanx,
dy=dx/(1+x^2)
x=1,dx=0.02, dy=0.02/2=0.01
所以arctan1.02=arctan1+0.01=π/4+0.01