F'(x)=f(x) 是错误的.
F(x)=∫[a~x] (x-t)f(t)dt=x∫[a~x] f(t)dt-∫[a~x] tf(t)dt,所以F'(x)=∫[a~x] f(t)dt,F'(a)=0,F''(x)=f(x),F''(a)=0
lim(x→a) F(x)/(x-a)^k 用洛必达法则
=lim(x→a) F'(x)/[k(x-a)^(k-1)]
=1/k×lim(x→a) F'(x)/[(x-a)^(k-1)]
=1/k×1/(k-1)×lim(x→a) F''(x)/[(x-a)^(k-2)]
=1/k×1/(k-1)×lim(x→a) f(x)/[(x-a)^(k-2)]
=1/k×1/(k-1)×1/(k-2)×lim(x→a) f'(x)/[(x-a)^(k-3)]
分子的极限是f'(a)≠0,所以k-3=0,k=3