(3x+1)^2 = 4(x-2)^2(3x+1)^2 - 4(x-2)^2 = 0 [(3x+1)+2(x-2)][(3x+1)-2(x-2)] = 0 (5x-3)(x+5) = 0 x1 = 3/5 , x2 = -5
