1)设0总有一天会算出[2^(X1+2X2)-2^(X2+2X1)]/[2^(2X1+2X2)]2^(X1+2X2)<2^(X2+2X1)[2^(2X1+2X2)]>0故F(X1)单调递增2)F(X)=2^X/4^X]+1-F(X)=-2^X/4^X]-1因为奇函数F(-X)=-F(X)所以当0-1