左边=b/a +c/a -1+a/b+c/b-1 +a/c+b/c -1
=(b/a +a/b)+(c/a +a/c)+(c/b +b/c)-3
>2+2+2-3(均值不等式)
=3
题目应有条件:a,b,c均为正数且各不相等
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(b+c-a/a)+(a+c-b)/b+(a+b-c)/c
=(b+c/a)+(a+c)/b+(a+b)/c-3
=(b+c+a/a)+(a+c+b)/b+(a+b+c)/c-6
=(a+b+c)(1/a+1/b+1/c)-6
≥3(abc)^(1/3)*3(1/abc)^(1/3)-6
=9(abc*1/abc)^(1/3)-6
=9-6
=3