原式=∫(0,1)x√(1+1^2)dx+∫(0,1)√x*√(1+1/4x)dx=(√2/2)x^2|(0,1)+(2/3)*(x+1/4)^(3/2)|(0,1)=√2/2+[5√5-1]/12=(6√2+5√5-1)/12
