(2y-1⼀3-y)눀≤1∴(y+2)(3y-4)≤0这步怎么来的???

2025-04-29 21:29:05
推荐回答(1个)
回答1:

(2y-1/3-y)²-1≤1-1

(y-1/3)²-1²≤0

(y-1/3+1)(y-1/3-1)≤0

(y+2/3)(y-4/3)≤0

1/3×1/3×(3y+2)(3y-4)≤0

9×1/3×1/3×(3y+2)(3y-4)≤0×9

(3y+2)(3y-4)≤0