令x+1=2
则x=1
所以f(2)=1²-3×1+2=0
令x+1=a
则x=a-1
所以f(a)=(a-1)²-3(a-1)+2=a²-5a+6
f(a)=a²-5a+6
所以f(x-1)
=(x-1)²-5(x-1)+6
=x²-7x+12
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