f(1/x)=(x+1)/(x-1)
f(x)+f(1/x)=[（x-1）/（x+1）]+[(x+1)/(x-1)]
通分 ={[(x-1)^2][(x+1)^2]}/[(x-1)(x+1)]
=2(x^2+1)/[(x+1)(x-1)]
=2(x^2+1)/(x^2-1)
f(x)=x-1/x+1
f(1/x)=1/x-x+1
f(x)+f(1/x)=2
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