解答过程”2(x-1)²=x-12(x-1)²-(x-1)=0(x-1)【2-(x-1)】=0(x-1)(3-x)=0得:x-1=0或3-x=0解得:x1=1,或x2=3答案是x=1或3
2(x-1)的平方=x-12[x^2-2x+1]=x-12x^2-4x+2=x-12x^2-5x+3=0(2x-3)(x-1)=0 十字相乘法x=3/2或x=1