a b两地相距360千米甲乙两车，同时从，a b两地出发相向而行经过2.5小时相遇，已知甲车每小时

解：设乙车每小时行x千米，则：甲车每小时行x-8千米。
[x+（x-8]×2.5=360
（x+x-8）×2.5=360
（ 2 x-8）×2.5=360
5x-20=360
5x=380
x=76
甲车每小时行：x-8=76-8=66（千米）
答：略
解法二：
2.5×8=20（千米）
360-20=340(千米 )
340÷2.5=136（千米）
136÷2=68（千米）
68+8=76（千米）

速度和是360÷2.5=144千米
甲是（144-8）÷2=68千米
乙是144-68=76千米

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