解:如图所示,在三角形ABC中,AB=AC=a,∠B=∠C=15°.作CD⊥BA于点D,则∠CAD=∠B+∠C=30°.∴在Rt△ADC中,CD= 1 2 AC= 1 2 a,S△ABC= 1 2 ×AB×CD= 1 2 ×a× 1 2 a= 1 4 a2.