高数 常微分方程 答案是f(x)=C⼀(x-1)∧2 我等于C∧2⼀(x-1)∧2 这类题

2025-03-21 06:33:35
推荐回答(1个)
回答1:

两边对 x 求导,得
f(x) + f(x) + (x-1)f'(x) = 0,
(x-1)f'(x) = -2f(x)
x ≠ 1 时, df(x)/f(x) = -2/(x-1),
ln[f(x)] = -2ln(x-1)+lnC
f(x) = C/(x-1)^2
x = 0 时,-f(0) = 1, f(0) = -1,
得 C= -1, 则 f(x) = -1/(x-1)^2