题意表达“[（x^3-2x^2+ax-1)-1]/(bx-1)=x^2-x+2”将[（x^3-2x^2+ax-1)-1]/(bx-1)=x^2-x+2变化为x^3-2x^2+ax-1=(bx-1)(x^2-x+2)+1=bx^3-(b+1)x^2+(2b+1)x-1观察x^3-2x^2+ax-1=bx^3-(b+1)x^2+(2b+1)x-1左右边对应系数知b=1,a=2b+1=3(b=1)故a=3b=1
