有两道初一数学题,求大家帮帮忙,急啊

(1) (-x^10)/(-x)^2+(-3x^4)^2(2) (x-4/x)*x/(x-2)
2024-11-22 17:22:53
推荐回答(3个)
回答1:

(1)(-x^10)/(-x)^2+(-3x^4)^2
=(-x^10)/x^2+9x^8
=-x^8+9x^8
=8x^8
(2)(x-4/x)*x/(x-2)
=(x^2-4)/(x-2)
=(x+2)(x-2)/(x-2)
=x+2

回答2:

(1) (-x^10)/(-x)^2+(-3x^4)^2=-x^8+9x^8=8x^8
(2) (x-4/x)*x/(x-2)=(x²-4)/(x-2)=(x+2)(x-2)/(x-2)=x+2

回答3:

(1)8X^8
(2)X+2