1.已知一对外啮合标准渐开线直齿圆柱齿轮传动,其标准中心距a=200mm,传动比i12=4,大齿轮齿数z2=80。试

2025-02-24 13:32:14
推荐回答(1个)
回答1:

m=200/(80+80/4)=2mm
z1=80/4=20
d2=2*80=160mm
da2=160+2.5*2=165mm
db2=160*cos20=150.35mm